Đáp án:
\(\begin{array}{l}
{m_{Cu}} = 4g\\
C{\% _{ZnS{O_4}}} = 10,05\%
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)Zn + C{\rm{uS}}{O_4} \to ZnS{O_4} + Cu\\
b)\\
{m_{{\rm{CuS}}{O_4}}} = \dfrac{{100 \times 10\% }}{{100\% }} = 10g\\
\to {n_{{\rm{CuS}}{O_4}}} = 0,0625mol\\
\to {n_{Cu}} = {n_{{\rm{CuS}}{O_4}}} = 0,0625mol\\
\to {m_{Cu}} = 4g
\end{array}\)
\(\begin{array}{l}
c)\\
{n_{ZnS{O_4}}} = {n_{Zn}} = {n_{{\rm{CuS}}{O_4}}} = 0,0625mol\\
\to {m_{ZnS{O_4}}} = 10,06g\\
{m_{Zn}} = 4,06g\\
{m_{{\rm{dd}}}} = {m_{Zn}} + {m_{{\rm{CuS}}{O_4}}} - {m_{Cu}} = 100,06g\\
\to C{\% _{ZnS{O_4}}} = \dfrac{{10,06}}{{100,06}} \times 100\% = 10,05\%
\end{array}\)