Đáp án:
$S =\left\{\log_2\dfrac{1 \pm\sqrt{13}}{2}\right\}$
Giải thích các bước giải:
$2^{2x} - 3 = 2^x$
$\to \left(2^x\right)^2 - 2^x - 3 = 0$
$\to \left[\begin{array}{l}2^x = \dfrac{1 -\sqrt{13}}{2}\\2^x = \dfrac{1 +\sqrt{13}}{2}\end{array}\right.$
$\to \left[\begin{array}{l}x = \log_2\dfrac{1 -\sqrt{13}}{2}\\x = \log_2\dfrac{1 +\sqrt{13}}{2}\end{array}\right.$
Vậy $S =\left\{\log_2\dfrac{1 \pm\sqrt{13}}{2}\right\}$
