Nghiệm của phương trình \({ \tan ^2}3x - \left( { \sqrt 3 - 1} \right) \tan 3x - \sqrt 3 = 0 \) là?
A.\(\left[ \begin{array}{l}x = - \dfrac{\pi }{{12}} + k\dfrac{\pi }{3}\\x = \dfrac{\pi }{9} + k\dfrac{\pi }{3}\end{array} \right.\,\left( {k \in \mathbb{Z}} \right).\)
B.\(x = - \dfrac{\pi }{{12}} + k\dfrac{\pi }{3}\,\,\left( {k \in \mathbb{Z}} \right).\)
C.\(\left[ \begin{array}{l}x = - \dfrac{\pi }{{12}} + k\dfrac{{2\pi }}{3}\\x = \dfrac{{2\pi }}{9} + k\dfrac{{2\pi }}{3}\end{array} \right.\,\left( {k \in \mathbb{Z}} \right).\)
D.\(\left[ \begin{array}{l}x = - \dfrac{\pi }{{12}} + k\dfrac{\pi }{3}\\x = \dfrac{\pi }{{18}} + k\dfrac{\pi }{3}\end{array} \right.\,\left( {k \in \mathbb{Z}} \right).\)
A.\(\left[ \begin{array}{l}x = - \dfrac{\pi }{{12}} + k\dfrac{\pi }{3}\\x = \dfrac{\pi }{9} + k\dfrac{\pi }{3}\end{array} \right.\,\left( {k \in \mathbb{Z}} \right).\)
B.\(x = - \dfrac{\pi }{{12}} + k\dfrac{\pi }{3}\,\,\left( {k \in \mathbb{Z}} \right).\)
C.\(\left[ \begin{array}{l}x = - \dfrac{\pi }{{12}} + k\dfrac{{2\pi }}{3}\\x = \dfrac{{2\pi }}{9} + k\dfrac{{2\pi }}{3}\end{array} \right.\,\left( {k \in \mathbb{Z}} \right).\)
D.\(\left[ \begin{array}{l}x = - \dfrac{\pi }{{12}} + k\dfrac{\pi }{3}\\x = \dfrac{\pi }{{18}} + k\dfrac{\pi }{3}\end{array} \right.\,\left( {k \in \mathbb{Z}} \right).\)
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Hóa Học lớp 12
