Đáp án:
\({m_{{C_2}{H_5}OH}} = 511,11{\text{ gam}}\)
Giải thích các bước giải:
Sơ đồ phản ứng:
\({C_6}{H_{10}}{O_5}\xrightarrow{{}}{C_6}{H_{12}}{O_6}\xrightarrow{{}}2{C_2}{H_5}OH + 2C{O_2}\)
Ta có:
\({m_{{C_6}{H_{10}}{O_5}}} = 1000 = 90\% = 900{\text{ gam}} \to {{\text{n}}_{{C_6}{H_{10}}{O_5}}} = \frac{{900}}{{162}} = \frac{{50}}{9}{\text{ mol}} \to {{\text{n}}_{{C_2}{H_5}OH}} = 2{n_{{C_6}{H_{10}}{O_5}}} = \frac{{100}}{9}{\text{ mol}}\)
\(\to {m_{{C_2}{H_5}OH}} = \frac{{100}}{9}.46 = 511,11{\text{ gam}}\)
