`B = | 1- 2^100| + | 5^50 - 2^100| - | 11- 5^50|`
Ta có: +) `1 < 2^100`
`=> | 1-2^100| = 2^100 -1`
+) `2^100 = (2^2)^50 = 4^50 < 5^10`
`=> |5^50 - 2^100| = 5^50 - 2^100`
+) `11 < 5^50`
`=> |11 - 5^50| = 5^50 -11`
Lúc đó `B= 2^100 - 1 + 5^50 - 2^100 - ( 5^50 -11)`
`B= 2^100 - 1 + 5^50 - 2^100 - 5^50 + 11`
`B= (2^100 -2^100) + ( 5^50 - 5^50) - ( 1 -11)`
`B= 10`
Vậy `B= 10`
