`| x - 1/2 | - 3/4 = 2/3`
`⇔ | x - 1/2 | = 2/3 + 3/4`
`⇔ | x - 1/2 | = 17/12`
`⇔` \(\left[ \begin{array}{l}x - 1/2 = 17/12\\x - 1/2 = -17/12\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}x = 23/12\\x = -11/12\end{array} \right.\)
Vậy , `x ∈ { 23/12 ; -11/12 }`