`q) 7^x + 2 + 2.7^x - 1 = 345`
`<=> 7^x . 7^2 + 2 . 7^x/7 = 345`
`<=> 7^x . (7^2 + 2/7) = 345`
`<=> 7^x . 345/7 = 345`
`<=> 7^x = 7`
`<=> x = 1`
Vậy `x = 1`
s) 81^-2x . 27^x = 9^5
<=> (3^4)^-2x . (3^3)^x = (3^2)^5
<=> 3^-8x . 3^3x = 3^10
<=> $3^{-8x + 3x}$ = 3^10
<=> -8x + 3x = 10
<=> -5x = 10
<=> x = -2
Vậy x = -2