Đáp án:
$0,45 M$
Giải thích các bước giải:
$\begin{gathered} Ba{(N{O_3})_2}\xrightarrow{{}}B{a^{2 + }} + 2NO_3^ - \hfill \\ \,\,\,\,\,\,\,\,\,0,45\,\,\,\,\, \to \,\,\,\,\,\,\,\,\,\,0,45\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,M \hfill \\ \end{gathered} $
Cation $Ba^{2+}: 0,45 M$