4na + o2----> 2na2o
6x 1.5x 3x
4al + 3o2-----> 2al2o3
2x 1.5x x
2X + o2-----> 2XO
3x 1.5x 3x
Theo đlbtkl, ta có
m o2 = 16.32-10.56=5.76(g)
=) n o2=5.76/32=0.18(mol)
b)
Do V o2 = 20% Vkk
=) V kk = 5 Vo2= 5*0.18*22.4=20.16(l)
b)
Do n na2o: n al2o3: n xo= 3:1:3
Gọi n al2o3 : x =) n na2o=n xo=3x
Có
1.5x + 1.5x +1.5x = 0.18
=) x= 0.04(mol)
=) m x = 10.56 - 6x*23-2x*27=10.56-7.68=2.88(g)
=) M X= 2.88/0.04*3=24(g/mol)
Vậy X là Magie(Mg)
%m Mg= 2.88/10.56*100%=27.3% (xấp xỉ)