Đáp án:
35,2175 l
Giải thích các bước giải:
\(\begin{array}{l}
{V_{{C_2}{H_5}OH}} = 1000 \times \frac{{90}}{{100}} = 900\,ml\\
{m_{{C_2}{H_5}OH}} = 900 \times 0,8 = 720g\\
{C_2}{H_5}OH + {O_2} \xrightarrow{\text{ lên men }} C{H_3}COOH + {H_2}O\\
{n_{{C_2}{H_5}OH}} = \dfrac{{720}}{{46}} = \dfrac{{360}}{{23}}\,mol\\
{n_{C{H_3}COOH}} = {n_{{C_2}{H_5}OH}} = \dfrac{{360}}{{23}}\,mol\\
H = 90\% \Rightarrow {m_{C{H_3}COOH}} = \dfrac{{360}}{{23}} \times 60 \times 90\% = 845,22g\\
{m_{{\rm{dd}}C{H_3}COOH}} = \dfrac{{845,22}}{{2\% }} = 42261g\\
{V_{{\rm{dd}}C{H_3}COOH}} = \dfrac{{42261}}{{1,2}} = 35217,5\,ml = 35,2175l
\end{array}\)
