Đáp án:
Giải thích các bước giải:
Ta nhúm quỳ tím vào dd
Dd chuyển đỏ lad H2SO4
Dd ko chuyển màu lag ZnCl2,ZnSO4
Sau đó ta nhỏ BaCl2 vào
Ta có thấy chất kết tủa là ZnSO4
Còn lại chất ko ht là ZnCl2
ZnSO4+BaCl2--->ZnCl2+BaSO4
Dùng quỳ tím
-H2SO4 làm quỳ hóa đỏ
-ZnCl2 và ZnSO4 ko làm quỳ đổi màu
Dùng BaCl2
-Xuất hiện kết tủa trắng
BaCl2+ZnSO4→BaSO4+ZnCl2
-Còn lại ZnCl2
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