Phân tích các đa thức sau thành nhân tử:
a. \(2{x^3}y - 50xy \)
b. \({x^2} - 6x - 4{y^2} + 9 \)
A.\(\begin{array}{l}a)\,\,2xy\left( {x - 5} \right)\left( {x + 5} \right)\\b)\,\,\left( {x - 3 - 2y} \right)\left( {x - 3 + 2y} \right)\end{array}\)
B.\(\begin{array}{l}a)\,\,2{x^2}y\left( {x - 5} \right)\left( {x + 5} \right)\\b)\,\,\left( {x + 3 - 2y} \right)\left( {x + 3 + 2y} \right)\end{array}\)
C.\(\begin{array}{l}a)\,\,2{x^2}y\left( {x - 5} \right)\left( {x + 5} \right)\\b)\,\,\left( {x - 3 - 2y} \right)\left( {x - 3 + 2y} \right)\end{array}\)
D.\(\begin{array}{l}a)\,\,2xy\left( {x - 5} \right)\left( {x + 5} \right)\\b)\,\,\left( {x + 3 - 2y} \right)\left( {x + 3 + 2y} \right)\end{array}\)
a. \(2{x^3}y - 50xy \)
b. \({x^2} - 6x - 4{y^2} + 9 \)
A.\(\begin{array}{l}a)\,\,2xy\left( {x - 5} \right)\left( {x + 5} \right)\\b)\,\,\left( {x - 3 - 2y} \right)\left( {x - 3 + 2y} \right)\end{array}\)
B.\(\begin{array}{l}a)\,\,2{x^2}y\left( {x - 5} \right)\left( {x + 5} \right)\\b)\,\,\left( {x + 3 - 2y} \right)\left( {x + 3 + 2y} \right)\end{array}\)
C.\(\begin{array}{l}a)\,\,2{x^2}y\left( {x - 5} \right)\left( {x + 5} \right)\\b)\,\,\left( {x - 3 - 2y} \right)\left( {x - 3 + 2y} \right)\end{array}\)
D.\(\begin{array}{l}a)\,\,2xy\left( {x - 5} \right)\left( {x + 5} \right)\\b)\,\,\left( {x + 3 - 2y} \right)\left( {x + 3 + 2y} \right)\end{array}\)
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