Đáp án:
Giải thích các bước giải:
`1)x^3-3x^2+3x+2`
`=(x^3-3x^2+3x-1)+3`
$=(x-1)^3+(\sqrt[3]{3})^3$
$=(x-1+\sqrt[3]{3} )[(x-1)^2-\sqrt[3]{3}.(x-1)+(\sqrt[3]{3})^2]$
$=(x-1+\sqrt[3]{3} )(x^2-2x+1-\sqrt[3]{3}x+\sqrt[3]{3}+(\sqrt[3]{3})^2]$
`2)(3x-1)^4+2(9x^2-6x+1)+1`
`=[(3x-1)^2]^2+2(3x-1)^2. 1+1^2`
`=[(3x-1)^2+1]^2`
`=(9x^2-6x+1+1)^2`
`=(9x^2-6x+2)^2`