Đáp án:
`=3.(49x+6)(51x+5)(100x+11)`
Giải thích các bước giải:
Đặt `a=49x+6,b=51x+5`
`=>a+b=49x+6+51x+5`
`=>a+b=100x+11`
`=>(100x + 11)^3 - (49x + 6)^3 - (51x + 5)^3`
`=(a+b)^3-a^3-b^3`
`=a^3+3a^2b+3ab^2+b^3-a^3-b^3`
`=3a^2b+3ab^2`
`=3ab(a+b)`
Thay `a=49x+6,b=51x+5` ta có:
`(100x + 11)^3 - (49x + 6)^3 - (51x + 5)^3`
`=3.(49x+6)(51x+5)(100x+11)`