Đáp án + Giải thích các bước giải:
$1)4x-1=(2\sqrt{x})^2-1^2=(2\sqrt{x}-1)(2\sqrt{x}+1)$
$2)x\sqrt{x} +27=(\sqrt{x})^3 +27=(\sqrt{x}+3)(x-3\sqrt{x}+9)$
$3)x-3\sqrt{x}-10=x-5\sqrt{x}+2\sqrt{x}-10$
$=\sqrt{x}(\sqrt{x}-5)+2(\sqrt{x}-5)=(\sqrt{x}-5)(\sqrt{x}+2)$
$4)x+6\sqrt{x}+8=(\sqrt{x})^2+2.\sqrt{x}.3+9 -1=(\sqrt{x}+3)^2-1$
$=(\sqrt{x}+3-1)(\sqrt{x}+3+1)=(\sqrt{x}+2)(\sqrt{x}+4)$
$5)x-4\sqrt{x}+4=(\sqrt{x})^2-2.\sqrt{x}.2+2^2=(\sqrt{x}-2)^2
$6)x-5\sqrt{x}+4=x-\sqrt{x}-4\sqrt{x}+4=\sqrt{x}(\sqrt{x}-1)-4(\sqrt{x}-1)$
$=(\sqrt{x}-1)(\sqrt{x}-4)$
Mk xin hay nhất ạ, mk rất cần ạ
