Bạn tham khảo:
1/$n^{3}-7n-6$
=$n^{3}+n^2-n^2-n-6n-6$
=$n^{2}.(n+1)-n(n+10-6(n+1)$
=$(n+1).($$n^{2}-n-6)$
=$(n+1)(n-3)(n+2)$
2/$n^{3}-7n+6$
=$n^{3}-2.n^2+2n^2-4n-3n+6$
=$n^{2}.(n-2)+2n(x-2)-3(n-2)$
=$(n-2)($$n^{2}+2n-3)$
=$(n-2).(n-1)(x+3)4
HỌC TỐT
@Chin...