Đáp án đúng: D
dung dịch AlCl3 + dung dịch NaOH.
$\begin{array}{l}\text{2Al}\,\text{+}\,\text{3}{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\,\xrightarrow{{}}\,\text{A}{{\text{l}}_{\text{2}}}{{\text{(S}{{\text{O}}_{\text{4}}}\text{)}}_{\text{3}}}\,\text{+}\,\text{3}{{\text{H}}_{\text{2}}}\uparrow \\\text{A}{{\text{l}}^{\text{3+}}}\,\text{+}\,\text{CO}_{\text{3}}^{\text{2-}}\,\text{+}\,{{\text{H}}_{\text{2}}}\text{O}\,\xrightarrow{{}}\,\text{Al(OH}{{\text{)}}_{\text{3}}}\downarrow \,\text{+}\,\text{C}{{\text{O}}_{\text{2}}}\uparrow \\\text{Al}\,\text{+}\,\text{NaOH}\,\text{+}\,{{\text{H}}_{\text{2}}}\text{O}\,\xrightarrow{{}}\,\text{NaAl}{{\text{O}}_{\text{2}}}\,\text{+}\,\frac{\text{3}}{\text{2}}{{\text{H}}_{\text{2}}}\uparrow \\\text{A}{{\text{l}}^{\text{3+}}}\,\text{+}\,\text{4O}{{\text{H}}^{\text{-}}}\,\xrightarrow{{}}\,\text{Al(OH)}_{\text{4}}^{\text{-}}\end{array}$
