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`P: Aa(BD)/(bd)` x `Aa(Bd)/(bd)`
Xét cặp `Aa` x `Aa`
`=> F_1: (1)/(4)A``A : (2)/(4)Aa: (1)/(4)aa`
Xét cặp `(BD)/(bd)` x `(Bd)/(bd)` có `f=40%`
`(BD)/(bd)` cho giao tử
`BD= bd= (1-f)/(2)=0,3`
`Bd = bD = (f)/(2) = 0,2`
`(Bd)/(bd)` cho giao tử
`Bd=bd = 0,5`
$*$ `F1` dị `3` cặp sẽ là:
`= Aa(BD)/(bd) + Aa(bD)/(Bd)`
`= 0,5.0,3.0,5 + 0,5.0,2.0,5= 12,5%`