Phép toán \(\frac{1}{{27}} - \frac{1}{9}\) được thực hiện đúng là:
A.\(\frac{1}{{27}} - \frac{1}{9} = \frac{0}{{18}}\)
B.\(\frac{1}{{27}} - \frac{3}{{27}} = \frac{{1 - 3}}{{27}} = \frac{{ - 2}}{{27}}\)
C.\(\frac{1}{{27}} - \frac{3}{{27}} = \frac{2}{{27}}\)
D.\(\frac{1}{{27}} - \frac{3}{{27}} = \frac{{ - 2}}{0}\)
A.\(\frac{1}{{27}} - \frac{1}{9} = \frac{0}{{18}}\)
B.\(\frac{1}{{27}} - \frac{3}{{27}} = \frac{{1 - 3}}{{27}} = \frac{{ - 2}}{{27}}\)
C.\(\frac{1}{{27}} - \frac{3}{{27}} = \frac{2}{{27}}\)
D.\(\frac{1}{{27}} - \frac{3}{{27}} = \frac{{ - 2}}{0}\)
Loga
Hóa Học lớp 12
