Đáp án đúng: B
Giải chi tiết:\(\eqalign{& \,\,\,\,\,\,\,{{x - 1} \over 2} + {{x - 1} \over 3} - {{x - 1} \over 6} = 2 \cr & \Leftrightarrow \left( {x - 1} \right)\left( {{1 \over 2} + {1 \over 3} - {1 \over 6}} \right) = 2 \cr & \Leftrightarrow \left( {x - 1} \right){4 \over 6}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 2 \cr & \Leftrightarrow x - 1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 3 \cr & \Leftrightarrow x\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 4 \cr & \Rightarrow S = \left\{ 4 \right\} \cr} \)
Chọn B.