`x-2=3`
`⇔x=5`
`A.x(x-2)=3x`
`⇔x^2-2x-3x=0`
`⇔x(x-5)=0`
⇔\(\left[ \begin{array}{l}x=0\\x-5=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=0\\x=5\end{array} \right.\)
`B.x-3=-2`
`⇔x=-2+3`
`⇔x=1`
`C.3(x-2)=6`
`⇔3x-6=6`
`⇔3x=12`
`⇔x=4`
`D.2(x-2)=6`
`⇔2x-4=6`
`⇔2x=10`
`⇔x=5`
Vậy đáp án là D.
Xin hay nhất ạ.