$P$ =( $\frac{1}{ \sqrt[]{a}-1} $ + $\frac{1}{a-\sqrt[]{a}}$ ) : $\frac{1}{\sqrt[]{a}-1}$
Với a ∈ R, A > 0, A khác 1
= ( $\frac{1}{ \sqrt[]{a}-1}$ + $\frac{1}{\sqrt[]{a}(\sqrt[]{a}-1)}$ ) : $\frac{1}{\sqrt[]{a}-1}$
= $\frac{ √a + 1 }{ √a( √a -1) }$. $√a -1 $
= $\frac{ √a+1 }{ √a }$
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