$Bài1:$
$a)$
$\frac{6x^2y^2}{8xy^5}=\frac{6x^2y^2 : 2xy^2}{8xy^5 : 2xy^2}=\frac{3x}{4y^3}$
$b)$
$\frac{x^2-xy}{5xy-5y^2}=\frac{x(x-y)}{5y(x-y)}=\frac{x}{5y}$
$Bài2:$
$a)$
$\frac{y}{3x}+\frac{2y}{3x}=\frac{y+2y}{3x}=\frac{3y}{3x}=\frac{y}{x}$
$b)$
$\frac{6x^3(2y+1)}{5y}.\frac{15}{2x^3(2y+1)}=\frac{9}{y}$