Đáp án:
$\begin{array}{l}\dfrac{2\sqrt{3}-\sqrt{6}}{\sqrt{8}-2}\\=\dfrac{2\sqrt{3}-\sqrt{6}}{2\sqrt{2}-2}\\=\dfrac{(2\sqrt{3}-\sqrt{6})(2\sqrt{2}+2)}{(2\sqrt{2}-2)(2\sqrt{2}+2)}\\=\dfrac{4\sqrt{6}+4\sqrt{3}-4\sqrt{3}-2\sqrt{6}}{8-4}\\=\dfrac{2\sqrt{6}}{4}\\=\dfrac{\sqrt{6}}{2}\end{array}$