Sắp xếp các hạng tử của mỗi đa thức theo lũy thừa giảm dần của biến x.
A.\(\begin{array}{l}f\left( x \right) = 6-3x+4{x^2}+2{x^3}+6{x^4}+5{x^5}\end{array}\)
\(\begin{array}{l}g\left( x \right) =5 - 5{x^5} - 2{x^4} + 2{x^3} + 4{x^2} - x \end{array}\)
B.\(\begin{array}{l}f\left( x \right) = 6-3x+4{x^2}+2{x^3}+6{x^4}+5{x^5}\end{array}\)
\(\begin{array}{l}g\left( x \right) = \, - 5{x^5} - 2{x^4} + 2{x^3} + 4{x^2} - x + 5\end{array}\)
C.\(\begin{array}{l}f\left( x \right) = -5{x^5} - 6{x^4} + 2{x^3} + 4{x^2} - 3x + 6\end{array}\)
\(\begin{array}{l}g\left( x \right) = \, 5{x^5} - 2{x^4} + 2{x^3} + 4{x^2} - x + 5\end{array}\)
D.\(\begin{array}{l}f\left( x \right) = 5{x^5} - 6{x^4} + 2{x^3} + 4{x^2} - 3x + 6\end{array}\)
\(\begin{array}{l}g\left( x \right) = \, - 5{x^5} - 2{x^4} + 2{x^3} + 4{x^2} - x + 5\end{array}\)
A.\(\begin{array}{l}f\left( x \right) = 6-3x+4{x^2}+2{x^3}+6{x^4}+5{x^5}\end{array}\)
\(\begin{array}{l}g\left( x \right) =5 - 5{x^5} - 2{x^4} + 2{x^3} + 4{x^2} - x \end{array}\)
B.\(\begin{array}{l}f\left( x \right) = 6-3x+4{x^2}+2{x^3}+6{x^4}+5{x^5}\end{array}\)
\(\begin{array}{l}g\left( x \right) = \, - 5{x^5} - 2{x^4} + 2{x^3} + 4{x^2} - x + 5\end{array}\)
C.\(\begin{array}{l}f\left( x \right) = -5{x^5} - 6{x^4} + 2{x^3} + 4{x^2} - 3x + 6\end{array}\)
\(\begin{array}{l}g\left( x \right) = \, 5{x^5} - 2{x^4} + 2{x^3} + 4{x^2} - x + 5\end{array}\)
D.\(\begin{array}{l}f\left( x \right) = 5{x^5} - 6{x^4} + 2{x^3} + 4{x^2} - 3x + 6\end{array}\)
\(\begin{array}{l}g\left( x \right) = \, - 5{x^5} - 2{x^4} + 2{x^3} + 4{x^2} - x + 5\end{array}\)
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