Đáp án: Ta có: $sin(\frac{x}{2}-\frac{x}{3})$=$\frac{-\sqrt{3}}{2}$
⇒ $\frac{x}{2}-\frac{x}{3}$=$-\frac{\pi}{3}+k2\pi$ hoặc $\frac{x}{2}-\frac{x}{3}$=$\frac{4\pi}{3}+k2\pi$
⇔ $\frac{x}{6}=$$-\frac{\pi}{3}+k2\pi$ hoặc $\frac{x}{6}=\frac{4\pi}{3}+k2\pi$
⇔ x=$-2\pi+k12\pi$hoặc $x=8\pi+k12\pi$