$\begin{array}{l} \sin \left( {\dfrac{{2x}}{3} - \dfrac{\pi }{3}} \right) = 0\\ \Leftrightarrow \dfrac{{2x}}{3} - \dfrac{\pi }{3} = k\pi \\ \Leftrightarrow \dfrac{{2x}}{3} = \dfrac{\pi }{3} + k\pi \\ \Leftrightarrow 2x = \pi + k3\pi \\ \Leftrightarrow x = \dfrac{\pi }{2} + \dfrac{{k3\pi }}{2}\left( {k \in \mathbb{Z}} \right) \end{array}$