Đáp án:
\(\left[ \begin{array}{l}x=\frac{arcsin(\frac{3}{4})}{2}+kπ\\x=\frac{-arcsin(\frac{3}{4})+π}{2}+kπ\end{array} \right.\) `(k ∈ Z)`
Giải thích các bước giải:
` sin2x = 3/4 `
` <=> ` \(\left[ \begin{array}{l}sin2x=\frac{3}{4}\\sin(π-2x)=\frac{3}{4}\end{array} \right.\)
` <=> ` \(\left[ \begin{array}{l}2x=arcsin(\frac{3}{4})\\π-2x=arcsin(\frac{3}{4})\end{array} \right.\)
` <=> ` \(\left[ \begin{array}{l}x=\frac{arcsin(\frac{3}{4})}{2}+kπ\\x=\frac{-arcsin(\frac{3}{4})+π}{2}+kπ\end{array} \right.\) `(k ∈ Z)`
