B = \(\dfrac{10^8+1}{10^9+1}\) < \(\dfrac{10^8+1+9}{10^9+1+9}\) (1) Ta có: \(\dfrac{10^8+1+9}{10^9+1+9}\) = \(\dfrac{10^8+10}{10^9+10}=\dfrac{10.\left(10^7+1\right)}{10.\left(10^8+1\right)}\) = \(\dfrac{10^7+1}{10^8+1}\)= A (2) Từ (1) và (2), suy ra: B < A hay: A > B.