Đáp án:
Bài 1:
( $\frac {1}{243}$ )⁶
= [ ( $\frac {1}{243}$ )² ]³
= ( $\frac {1}{59049}$ )³
Vì $\frac {1}{79}$ > $\frac {1}{59049}$
=> ( $\frac {1}{79}$ )³ > ( $\frac {1}{59049}$ )⁶
Vậy ( $\frac {1}{79}$ )³ > ( $\frac {1}{243}$ )³.
Bài 2:
$\frac {54.107 – 53}{53.107 + 54}$
= $\frac {54.107 + 54 + 1}{53.107 + 53 + 1}$
= $\frac {54.106 + 1}{53.108 + 1}$
= $\frac {54.(108 + 2) + 1}{54.108 + 108 + 1}$
= $\frac {54.108 + 54.2 + 1}{54.108 + 109}$
= $\frac {54.108 + 109}{54.108 + 109}$
= 1
