Đáp án:
Giải thích các bước giải:
\(\begin{array}{l}d)\,{5^{28}}\,\,\,va\,\,\,{26^{14}}\\Ta\,co:\,\,{5^{28}} = {\left( {{5^2}} \right)^{14}} = {25^{14}} < {26^{14}}\\f)\,{49^{10}}\,\,\,va\,\,{625^5}\\Ta\,co:\,\,{625^5} = {\left( {{5^4}} \right)^5} = {\left( {{5^2}} \right)^{10}} = {25^{10}} < {49^{10}}\\g)\,{444^5}\,\,\,\,va\,\,{555^4}\\{444^5} = {\left( {4.111} \right)^5} = {4^5}{.111^5} = {1024.111^5}\\{555^4} = {\left( {5.111} \right)^4} = {5^4}{.111^4} = {625.111^4}\\ \Rightarrow {1024.111^5} > {625.111^4}\,\,\,\,\,\,hay\,\,\,{444^5} > {555^4}\end{array}\)
