Cho tam giác ABC, \(\angle B = {40^0};\angle C = {30^0}\), đường cao \(AH{\rm{ }} = {\rm{ 6}}cm\). Tính AB, AC và BC.
A.\(AB = 8,26\,\,;\,\,\,AC = 10\,\,;\,\,BC = 6,65 + 6\sqrt 2 \)
B.\(AB = 9,33\,\,;\,\,\,AC = 10\,\,;\,\,BC = 7,15 + 6\sqrt 2 \)
C.\(AB = 8,26\,;\,\,\,AC = 12\,\,;\,\,BC = 6,65 + 6\sqrt 3 \)
D.\(AB = 9,33\,\,;\,\,\,AC = 12\,\,;\,\,BC = 7,15 + 6\sqrt 3 \)