Tập xác định của hàm số $y={{\log }_{0,3}}\left( {{x}^{3}}-1 \right)$ làA.$\left( 1;+\infty \right)$.B.$\left( -\infty -1 \right)\cup \left( 1;+\infty \right)$.C.$\left( -\infty -1 \right)$.D.$\left( -1;1 \right)$.
Trong các phân số sau $ \dfrac{50}{40};\dfrac{60}{48};\dfrac{10}{8};\dfrac{6}{4};\dfrac{15}{12};\dfrac{25}{20};\dfrac{5}{4}. $ Phân số không bằng phân số còn lại làA. $ \dfrac{5}{4}. $ B. $ \dfrac{10}{8}. $ C. $ \dfrac{15}{12}. $ D. $ \dfrac{6}{4}. $
Cho các phân số $ \dfrac{-9}{39};\dfrac{12}{9};\dfrac{2}{14};\dfrac{-3}{13};\dfrac{-35}{10};\dfrac{5}{3};\dfrac{4}{3};\dfrac{-7}{2} $. Số cặp phân số bằng nhau làA.1 cặp.B.3 cặp.C.2 cặp.D.4 cặp.
Tập xác định D của hàm số $y={{\log }_{3}}({{x}^{2}}-4x+3)$ làA.$D=(1;3)$.B.$D=(-\infty ;2-\sqrt{2})\cup (2+\sqrt{2};+\infty )$.C.$D=(2-\sqrt{2};1)\cup (3;2+\sqrt{2})$.D.$D=(-\infty ;1)\cup (3;+\infty )$.
Đa thức A thỏa mãn để $ \dfrac{A}{2x-1}=\dfrac{6{{x}^{2}}+3x}{4{{x}^{2}}-1} $ làA.$ A=3x $.B.$ A=-4x $.C.$ A=2x-1 $.D.$ A=2x $.
Mark the letter A, B, C, or D to indicate the correct answer to each of the following questions. He may be shy now, but he’ll soon come out of his ______ when he meets the right girl.A.shedB.holeC.shellD.shoe
Mark the letter A, B, C, or D on your answer sheet to indicate the correct answer to each of the following questions. She _______ me a very charming compliment on my paintingA.paidB.tookC.showedD.made
Mark the letter A, B, C, or D to indicate the correct answer to each of the following questions. “I’m going for an interview for a job this afternoon.” - “Good luck! I’ll keep my _____crossed for you”A.handsB.legsC.armsD.fingers
Mark the letter A, B, C, or D to indicate the correct answer to each of the following questions. I’m not surprised that Tom is ill. He’s been _____ for a long time. It was bound to affect his health sooner or later.A.going to townB.having his cake and eating itC.playing with fireD.burning the candle at both ends
Choose the best answer. Tell me what happened ______ your own words.A.inB.onC.byD.with
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