Đáp án đúng: B Vì $ n=\dfrac{V}{22,4}\to V=22,4.n $ $ \begin{array}{l} {{n}_{{{O}_{2}}}}=\dfrac{{{m}_{{{O}_{2}}}}}{{{M}_{{{O}_{2}}}}}=\dfrac{24}{32}=0,75\,(mol)\to {{V}_{{{O}_{2}}}}={{n}_{{{O}_{2}}}}.22,4=0,75.22,4=16,8\,(l) \\ {{n}_{{{N}_{2}}}}=\dfrac{{{m}_{{{N}_{2}}}}}{{{M}_{{{N}_{2}}}}}=\dfrac{28}{28}=1\,(mol)\to {{V}_{{{N}_{2}}}}={{n}_{{{N}_{2}}}}.22,4=1.22,4=22,4\,(l) \\ {{n}_{C{{O}_{2}}}}=\dfrac{{{m}_{C{{O}_{2}}}}}{{{M}_{C{{O}_{2}}}}}=\dfrac{88}{12+16.2}=2\,(mol)\to {{V}_{{{N}_{2}}}}=2.22,4=44,8\,(l) \\ {{n}_{C{{l}_{2}}}}=\dfrac{{{m}_{C{{l}_{2}}}}}{{{M}_{C{{l}_{2}}}}}=\dfrac{35,5}{35,5.2}=0,5\,(mol)\to {{V}_{C{{l}_{2}}}}=0,5.22,4=11,2\,(l) \end{array} $ $ \to $ Thể tích của 88 gam khí cacbonic là lớn nhất