Đáp án:
`1)(\frac{1}{2}x^2y^3)^3(\frac{2}{3}xy)^2=(1)/(18)x^8y^11`
`2)(1/(2x^2y^3))^3(2/(3xy))^2=(1)/(18x^8y^11)`
Giải thích các bước giải:
Đề `1`:
`(\frac{1}{2}x^2y^3)^3(\frac{2}{3}xy)^2`
`=((1/2)^3(x^2)^3(y^3)^3)((2/3)^{2}.x^{2}.y^2`
`=(\frac{1}{8}x^6y^9)(\frac{2^2}{3^2}.x^2y^2)`
`=(\frac{1}{8}x^6y^9)(\frac{4}{9}x^2y^2`
`=1/(8).(4)/(9).(x^{6}.x^{2}).(y^{9}.y^2)`
`=(1)/(2).(1)/(9).x^{6+2}.y^{9+2}`
`=(1)/(18)x^8y^11`
Đề `2`
`(1/(2x^2y^3))^3(2/(3xy))^2`
`=(1^3/(2x^2y^3)^3)(2^2/(3xy)^2)`
`=(1/(2^{3}.(x^2)^{3}.(y^3)^3))(4/(3^{2}.x^{2}.y^2))`
`=(1/(8x^6y^9)).(4/(9x^2y^2))`
`=\frac{1.4}{(8x^6y^9).(9x^2y^2)}`
`=\frac{4}{(8.9).(x^{6}.x^2).(y^{9}.y^2)}`
`=(4)/(72x^8y^11)`
`=(1)/(18x^8y^11)`
