Đáp án:

$1/ 2³ . 2 = 2³ . 2^{1} = 2^{3+1} = 2^{4}$  

$2/ (-2)^{5} . (-2)^{6} = (-2)^{5+6} = (-2)^{11}$ 

$3/ (-0,2)^{4} . (-0,2)^{5} = (-0,2)^{4+5} = (-0,2)^{9}$

$4/ (\frac{3}{2})^{3} . (\frac{3}{2})^{2} = (\frac{3}{2})^{3+2} = (\frac{3}{2})^{5}$

$5/ (-\frac{1}{2})$ . $(-\frac{1}{2})^{3} = (-\frac{1}{2})^{1} . (-\frac{1}{2})^{3} = (-\frac{1}{2})^{1+3} = (-\frac{1}{2})^{4}$

$6/ (\frac{-7}{8})^{2} . (\frac{-7}{8})^{3} = (\frac{-7}{8})^{2+3} = (\frac{-7}{8})^{5}$

$7/ (-2)^{3} . 2^{2} = (-2)^{3} . (-2)^{2} = (-2)^{3+2} = (-2)^{5}$

$8/ (-5)^{7} . 5^{4} = (-5)^{7} . (-5)^{4} = (-5)^{7+4} = (-5)^{11}$
$9/ (\frac{2}{3})^{5} . (\frac{-2}{3})^{4} = (\frac{2}{3})^{5} . (\frac{2}{3})^{4} = (\frac{2}{3})^{5+4} = (\frac{2}{3})^{9}$
$10/ x . x = x^{1} . x^{1} = x^{1+1} = x^{2}$ 
$11/ (-x)^{3} . (-x)^{6} = (-x)^{3+6} = (-x)^{9}$ 
$12/ (-x) . x^{2} = (-x)^{1} . (-x)^{2} = (-x)^{1+2} = (-x)^{3}$
$13/ (-x)^{10} . x^{3} = x^{10} . x^{3} = x^{10+3} = x^{13}$ 

HỌC TỐT~~

#NOCOPY

#NOTHINGISIMPOSSIBLE

1) 2^3 x2 = 2^ 3+1 = 2^4 

2) (-2)^5 x(-2)^6= (-2)^ 5+6=(-2) ^11

3) (-0.2)^4 x (-0.2)^5 = (-0.2)^4+5=(-0.2)^9

4) (3/2)^3 x (3/2) ^2= (3/2)^3+2= (3/2)^5

5) (-1/2) x (-1/2)^3= (-1/2) ^ 1+3 = (-1/2) ^4 

6) (-7/8)^2 x ( -7/8 )^3 = (-7/8)^2+3=(-7/8)^5

8) (-5)^7 x5^4 = (-1) x ( -5) ^7+4=(-1) x 5^11 = (-5)^11

7) (-2)^3 x 2^2=(-1) x 2^3+2= (-2)^5)

9)  (2/3)^5 x (2/3)^4 = (-1) x (2/3)^5+4 = (-2/3)^9

10) x . x= x^1. x^1= x^1+1=x²

11)  (-x)³ .(-x)^6= (-x) ^ 3+6=(-x)^9

12) (-x) . x² = (-1) . (x)^1+2=(-x)^3

13) (-x)^10 . x³ = (-1) . x^10+3 =(-x)^13

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