Đáp án:
$C2H4 -(1)-> C2H5OH -(2)-> CH3COOH -(3)-> CH3COONa -(4)-> CH3COOH -(5)-> CH3COOC2H5$
$C2H4 + H2O -$xt axit$-> C2H5OH$
$C2H5OH + O2 -$Men giấm$-> CH3COOH + H2O$
$CH3COOH + NaOH --> CH3COONa + H2O$
$CH3COOH + HCl -xt-> CH3COOH + NaCl$
$CH3COOH + C2H5OH -140^{o}C, xt H2SO4 đ-> CH3COOC2H5 + H2O$