Cứ 1 mol mantozơ thuỷ phân tạo 2 mol glucozơ.
$n_{C_{12}H_{22}O_{11}}=\dfrac{205,2}{342}=0,6(mol)$
$\Rightarrow n_{C_6H_{12}O_6}=2n_{C_{12}H_{22}O_{11}\text{pứ}}=2.0,6.60\%=0,72(mol)$
$n_{C_{12}H_{22}O_{11}\text{dư}}=0,6.40\%=0,24(mol)$
$\Rightarrow n_{Ag}=2.0,72+2.0,24=1,92(mol)$
$\to m=108.1,92=207,36g$