Đáp án:
`(8x-8x^3-10x^2+3x^4-5):(3x^2-2x+1)`
`= \frac{8x-8x^3-10x^2+3x^4-5}{3x^2-2x+1}`
`= \frac{-2x+10x-2x^3-6x^3+x^2+4x^2-15x^2+3x^4-5}{3x^2-2x+1}`
`= \frac{-2x(3x^2-2x+1)-5(3x^2-2x+1)+x^2(3x^2-2x+1)}{3x^2-2x+1}`
`= \frac{(3x^2-2x+1)(x^2-2x-5)}{3x^2-2x+1}`
`= x^2-2x-5`