@isa
Học tốt nek 0_0
1.
a, ( 2x + 1 ) ( 6x - 5 )
= 12$x^{2}$ - 10x + 6x -5
= $x^{2}$ - 4x - 5
b, ( 16x³y² - 8x² ) : 4x²
= 4xy² -2
= 2( 2xy² -1 )
c, $\frac{x^2y + 2x}{6xy}$ + $\frac{2x^2y-2x}{6xy}$
= $\frac{x^2y + 2x + 2x^2y-2x}{6xy}$
= $\frac{3x^2y}{6xy}$
= $\frac{x}{2}$
d, $\frac{1}{x-2}$ - $\frac{3}{(x-2)(2x-1)}$
= $\frac{2x-1}{(x-2)(2x-1)}$ - $\frac{3}{(x-2)(2x-1)}$
= $\frac{2x-1-3}{(x-2)(2x-1)}$
= $\frac{2x-4}{(x-2)(2x-1)}$
= $\frac{2}{2x-1}$