$b) \frac{12}{7}.\frac{2}{5}+\frac{2}{5}.(\frac{-5}{7})$
$=\frac{2}{5}.[\frac{12}{7}+(\frac{-5}{7})]$
$=\frac{2}{5}.(\frac{12}{7}-\frac{5}{7})$
$=\frac{2}{5}.\frac{7}{7}$
$=\frac{2}{5}.1$
$=\frac{2}{5}$
$c) \frac{2}{3} + 2x = -\frac{4}{3}$
$→ 2x=(-\frac{4}{3})$$-\frac{2}{3}$
$→ 2x=\frac{-6}{3}$
$→ 2x=-2$
$→ x=-1$