Đáp án:
b)$\frac{-4}{5}$
c)$\frac{1}{71}$
d)$\frac{-29}{5}$
i)$\frac{-147}{13}$
Giải thích các bước giải:
b) ($\frac{5}{7}$-$\frac{7}{5}$)-[ $\frac{1}{2}$-(-$\frac{2}{7}$-$\frac{1}{10}$)]
=$\frac{-24}{35}$-( $\frac{1}{2}$+ $\frac{-27}{70}$)
=$\frac{-24}{35}$-$\frac{4}{35}$
=$\frac{-28}{35}$=$\frac{-4}{5}$
c)(-$\frac{1}{2}$)-(- $\frac{3}{5}$)+(-$\frac{1}{9}$)+ $\frac{1}{71}$-(-$\frac{2}{7}$)+ $\frac{4}{35}$- $\frac{7}{18}$
=-$\frac{1}{2}$+ $\frac{3}{5}$- $\frac{1}{9}$+ $\frac{1}{71}$+ $\frac{2}{7}$+ $\frac{4}{35}$-$\frac{7}{18}$
=$\frac{1}{71}$
d)(3-$\frac{1}{4}$+ $\frac{2}{3}$)-(5- $\frac{1}{3}$- $\frac{6}{5}$)-(6-$\frac{7}{4}$+ $\frac{3}{2}$)
=$\frac{41}{12}$-$\frac{52}{15}$-$\frac{23}{4}$
=$\frac{41}{12}$-$\frac{553}{60}$
=$\frac{-29}{5}$
i)(-$\frac{3}{4}$+ $\frac{5}{13}$): $\frac{2}{7}$-(2$\frac{1}{4}$+ $\frac{8}{13}$): $\frac{2}{7}$
=($\frac{-3}{4}$+ $\frac{5}{13}$-2$\frac{1}{14}$+$\frac{8}{13}$):$\frac{2}{7}$
=$\frac{-42}{13}$ :$\frac{2}{7}$
=$\frac{-147}{13}$
