Đáp án đúng: D
Giải chi tiết:\(0,1\,mol\,HCOOCH = C{H_2}\) \(\xrightarrow[H=60\%]{H_2O,xt\,H^+}\) \(\left\{ \begin{array}{l}HCOOH\,0,06\,mol\\C{H_3}CHO\,0,06\,mol\\HCOOCH = C{H_2}\,0,04\,mol\,(du)\end{array} \right.\) \(\overset{AgNO_3/NH_3}{\rightarrow}\) \(Ag\)
\(0,2\,mol\,Sac\) \(\xrightarrow[H=60\%]{H_2O,xt\,H^+}\) \(\left\{ \begin{array}{l}Glu\,0,12\,mol\\Fruc\,0,12\,mol\\Sac\,0,08\,mol\,(du)\end{array} \right.\) \(\overset{AgNO_3/NH_3}{\rightarrow}\) \(Ag\)
\(\begin{array}{l} \Rightarrow {n_{Ag}} = 2({n_{HCOOH\,}} + {n_{C{H_3}CHO}} + {n_{HCOOCH = C{H_2}}} + {n_{Glu}} + {n_{Fruc}}) = 0,8\,mol\\ \Rightarrow {m_{Ag}} = 86,4\,gam.\end{array}\)
Đáp án D