Đáp án:
$\begin{array}{l}
giao\,diem\,cua\,y\,voi\,{\rm{Ox}}\,{\rm{co\, toa}}\,{\rm{do}}\,{\rm{y = }}\frac{{x - 1}}{{x - 2}} = 0\\
\to x = 1 \to A(1;0)\\
co\,y' = \frac{{ - 1}}{{{{(x - 2)}^2}}}\\
pt\,tiep\,tuyen\,cua\,dths\,co\,pt:\\y = y{'_{{x_0}}}(x - {x_0}) + {y_{{x_0}}}\\
y = \frac{{ - 1}}{{{{(1 - 2)}^2}}}.(x - 1) + 0\\
y = x - 1
\end{array}$