\(\left|\left|x\right|-15\right|=10\)
\(\left|x\right|-15=\pm10\)
TH1:
\(\left|x\right|-15=10\)
\(\left|x\right|=10+15\)
\(\left|x\right|=25\)
\(x=\pm25\)
TH2:
\(\left|x\right|-15=-10\)
\(\left|x\right|=-10+15\)
\(\left|x\right|=5\)
\(x=\pm5\)
Vậy \(x\in\left\{-25;-5;5;25\right\}\)
