Đáp án+Giải thích các bước giải:
`(1-2x)(1+2x)-x(x+2)(x-2)=0`
`=> [12+(2x)^2]-x(x^2 -2^2)=0`
`=> (1+4.2)-x(x^2 -4)=0`
`=> (1+4.2)-(x^3 -4x)=0`
`=> 1+4.2-x^3 +4x=0`
`=> (1+x^3 )-(4.2-4x)=0`
`=> -(x^3 -1)-(4.2+4x)=0`
`=>-(x-1)(x^2 +x+1)-4x(x-1)=0`
`=> -(x-1)(x^2 +x+1+4x)=0`
`=> -(x-1)(x^2 +5x+1)=0`
`TH1:``-x+1=0`
`=>-x=-1`
`=>x=1` `(tm)`
`TH2:``x^2 +5x+1=0` `(kotm)`
$\begin{array}{|c|}\hline \text{}&\text{Vậy x=1}&\text{}\\\hline\end{array}$
