`x + ( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 60 ) = 2074`
`=> \underbrace{x + x + x + ... + x}_{61 số x} + \underbrace{1 + 2 + 3 + ... + 60}_{60 số hạng} = 2074`
`=> 61x + [(60 + 1 ) × 60 : 2] = 2074`
`=> 61x + [61 × 60 : 2] = 2074`
`=> 61x + [3660 : 2] = 2074`
`=> 61x + 1830 = 2074`
`=> 61x = 2074 - 1830`
`=> 61x = 244`
`=> x = 244 : 61`
`=> x = 4`
Vậy `x = 4`
`#dtkc`