$\textit{Đáp án + Giải thích các bước giải:}$
$\text{$|x - 1|^{}$ = $3x^{}$ + 2}$
$\text{$x^{}$ - 1 = ± $(3x + 2)^{}$}$
$\text{Nếu $x^{}$ - 1 = $3x^{}$ + 2 ($x^{}$ $\geq$ 1)}$
$\text{$x^{}$ - $3x^{}$ = 2 - 1}$
$\text{$-2x^{}$ = 3}$
$\text{$x^{}$ = $\dfrac{-3}{2}$ (ktm)} $
$\text{Nếu $x^{}$ - 1 = $-(3x + 2)^{}$ = $-3x^{}$ - 2 ($x^{}$ < 1)}$
$\text{$x^{}$ + $3x^{}$ = -2 + 1}$
$\text{$4x^{}$ = -1}$
$\text{$x^{}$ = $\dfrac{-1}{4}$ (tm)}$
$\text{Vậy $x^{}$ = $\dfrac{-1}{4}$}$
