Đáp án:
1, 3x ³ - 4x ² = 0
<=>x² (3x-4)=0
<=>\(\left[ \begin{array}{l}x=0\\x=4/3\end{array} \right.\)
2)2x ( x + 1) - 3x - 3 = 0
<=>2x ( x + 1) - 3(x+1) = 0
<=> ( x+1) - (2x -3) = 0
<=>\(\left[ \begin{array}{l}x=3/2\\x=-1\end{array} \right.\)
3, x (2x - 1) - 8x + 4 = 0
<=> x (2x - 1) - 4(2x - 1) = 0
<=>(2x - 1) (x-4)=0
<=> \(\left[ \begin{array}{l}x=1/2\\x=4\end{array} \right.\)
4, x ² - 6x + 5 = 0
<=>x² -5x -x+5 =0
<=> x( x-5) -( x-5) =0
<=> (x-1)( x-5) =0
<=>\(\left[ \begin{array}{l}x=1\\x=5\end{array} \right.\)
Giải thích các bước giải:
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