$1)|x-5|=12$
⇒\(\left[ \begin{array}{l}x-5=12\\x-5=-12\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=12+5\\x=-12+5\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=17\\x=-7\end{array} \right.\)
Vậy $x∈${$-7;17$}
$2)|3x-12|=x+2$
⇒\(\left[ \begin{array}{l}3x-12=x+2(x\geq4)\\-(3x-12)=x+2(x<4)\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=7\\x=\frac{5}{2}\end{array} \right.\)
Vậy $x∈${$7;\frac{5}{2}$ }
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